A) +11.2
B) -11.2
C) -8.8
D) +8.8
Correct Answer: D
Solution :
[d] Given, Focal length of objective, \[{{f}_{0}}=30cm\] Focal length of eye lens, \[{{f}_{e}}=3.0cm\] Magnifying power, M=? Magnifying power of the Galilean telescope, \[{{M}_{D}}=\frac{{{f}_{0}}}{{{f}_{e}}}\left( 1-\frac{{{f}_{e}}}{D} \right)=\frac{30}{3}\left( 1-\frac{3}{25} \right)\left[ \because D=25cm \right]\] \[=10\times \frac{22}{25}=8.8cm\]You need to login to perform this action.
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