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JEE Main & Advanced Physics Ray Optics Question Bank Self Evaluation Test - Ray Optics and Optical Instruments

  • question_answer
    In Fig. ABC is the cross section of a right - angled prism and ACDE is the cross section of a glass slab. The value of 9 so that incident normally on the face AB does not cross the face AC is\[\left( \text{given si}{{\text{n}}^{-1}}(3/5)=37{}^\circ  \right)\].    

    A) \[\theta \le 37{}^\circ \]

    B) \[\theta \le 37{}^\circ \]

    C) \[\theta \ge 53{}^\circ \]

    D) \[\theta >53{}^\circ \]

    Correct Answer: B

    Solution :

    [b] \[A=90{}^\circ -\theta \] \[\Rightarrow {{r}_{2}}=A=90{}^\circ -\theta >{{\theta }_{c}}\] \[\cos \theta >sin{{\theta }_{c}}=\frac{6/5}{2/3}=\frac{4}{5}\] \[\left( {{\theta }_{c}}\text{ is critical angle} \right)\] \[\theta <{{\cos }^{-1}}\frac{4}{5}=37{}^\circ \]


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