JEE Main & Advanced Physics Ray Optics Question Bank Self Evaluation Test - Ray Optics and Optical Instruments

  • question_answer
    A transparent sphere of radius R has a cavity of radius R/2 as shown in figure. Find the refractive index of the sphere if a parallel beam of light falling on left surface focuses at point P.        

    A) \[\mu =\frac{3+\sqrt{5}}{2}\]   

    B) \[\mu =\frac{3-\sqrt{5}}{2}\]

    C) \[\mu =3+\sqrt{5}\]

    D) \[\mu =\frac{1+\sqrt{5}}{2}\]

    Correct Answer: A

    Solution :

    [a] Let refractive index of glass be\[\mu \]. Let after first refraction, image distance be v then \[\frac{\mu }{v}-\frac{1}{\infty }=\frac{\mu -1}{R}\Rightarrow v=\frac{\mu R}{\mu -1}\] Now second refraction will take place. So distance of first image from O is \[{{u}_{1}}=\frac{\mu R}{\mu -1}-R=\frac{R}{\mu -1}\] and image is formed at R \[\therefore \frac{1}{R}-\frac{\mu \left( \mu -1 \right)}{R}=\frac{2\left( 1-\mu  \right)}{R}\] \[\Rightarrow {{\mu }^{2}}-3\mu +1=0\text{    So, }\mu =\frac{3+\sqrt{5}}{2}\]


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