A) +1.5
B) -1.5
C) +6.67
D) -6.67
Correct Answer: B
Solution :
[b] \[{{f}_{1}}=+40cm=0.4m\] (for convex lens) \[{{f}_{2}}=-25cm=-0.25m\] (for concave lens) \[\therefore \]Focal length (f) of the combination \[\frac{1}{f}=\frac{1}{{{f}_{1}}}+\frac{1}{{{f}_{2}}}=\frac{1}{0.40}-\frac{1}{0.25}=\frac{0.25-0.4}{0.40\times 0.25}\] \[=-\frac{0.15}{0.1}=-1.5\text{ dioptre}\text{.}\Rightarrow \text{P=}\frac{1}{f}=-1.5\text{ dioptre}\]You need to login to perform this action.
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