A) 15 cm
B) 20cm
C) -18.31cm
D) 10cm
Correct Answer: C
Solution :
[c] The image I' for first refraction (i.e., when the ray comes out of liquid) is at a depth of \[=\frac{33.25}{1.33}=25cm\left[ \therefore \text{Apparent depth=}\frac{\text{Real depth}}{\mu } \right]\]Now, reflection will occur at concave mirror. For this F behaves as an object. Where \[\frac{25}{1.33}\] is the real depth of the image? Using mirror formula we get \[\frac{1}{f}=\frac{1}{v}+\frac{1}{u},f=-18.31cm\]You need to login to perform this action.
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