A) \[15\times 3\times \sqrt{5}cm\]
B) \[15\times 3\sqrt{7}cm\]
C) \[\frac{15\times \sqrt{7}}{3}cm\]
D) \[\frac{15\times 3}{\sqrt{7}}cm\]
Correct Answer: D
Solution :
[d] Given, \[u=\frac{4}{3}h=15cm\] \[\frac{\sin 90{}^\circ }{\sin C}=\mu \Rightarrow \sin C=\frac{1}{\mu }=\frac{R}{\sqrt{{{R}^{2}}+{{h}^{2}}}}=\frac{3}{4}\] \[\Rightarrow 16{{R}^{2}}=9{{R}^{2}}+{{h}^{2}}\text{ or, }7{{R}^{2}}\text{ =9}{{\text{h}}^{2}}\] \[\text{or, }R=\frac{3}{\sqrt{7}}h=\frac{3}{\sqrt{7}}\times 15cm\]
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