A) \[2h-d\left( \frac{\mu }{\mu -1} \right)\]
B) \[2h-\frac{d}{2}\left( \frac{\mu -1}{\mu } \right)\]
C) \[2h-d\left( \frac{\mu -1}{\mu } \right)\]
D) \[2h-d\left( \frac{2\mu -1}{\mu } \right)\]
Correct Answer: C
Solution :
[c] The distance of bottom of the beaker from mirror \[=h-d\left( 1-\frac{1}{\mu } \right)\] So it will be at a distance \[=h-d\left( 1-\frac{1}{\mu } \right)\] from mirror. Now distance between bottom of beaker and image \[=h+h-d\left( 1-\frac{1}{\mu } \right)=2h-d\left( \frac{\mu -1}{\mu } \right).\]
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