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JEE Main & Advanced Physics Ray Optics Question Bank Self Evaluation Test - Ray Optics and Optical Instruments

  • question_answer
    An object kept on the principle axis is moving in the same directions as that of mirror as shown in figure. Speed of object and mirror is 10m/s and 40/ 12 m/s. Radius of the curvature of the mirror is 20 cm. What should be the distance of object from the mirror at this instant so that the image is stationary?

    A) 25 cm

    B) 45 cm       

    C) 37.5 cm

    D) 15 cm                      

    Correct Answer: A

    Solution :

    [a] \[{{\vec{V}}_{im}}=\frac{{{V}^{2}}}{{{u}^{2}}}{{\vec{V}}_{om}}\] \[0-\frac{40}{13}=-{{\left( \frac{-10}{-10+x} \right)}^{2}}\left( 10-\frac{40}{13} \right)\] \[\frac{-10}{-10+x}=\pm \frac{2}{3}\] \[\ell \] Object is in front of mirror Hence 25 cm.


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