A) 1m
B) 0.5m
C) 0.5m
D) 025m
Correct Answer: D
Solution :
[d] For \[P:\frac{1}{v}+\frac{1}{u}=\frac{1}{f}\] \[\text{or }\frac{1}{{{v}_{P}}}+\frac{1}{-3}=\frac{1}{-1}\text{ or }{{\text{v}}_{P}}=-\frac{3}{2}m\] For \[Q:\frac{1}{{{v}_{Q}}}+\frac{1}{-5}=\frac{1}{-1}\text{ or }{{v}_{Q}}=\frac{-5}{4}m\] So horizontal distance between image of P and Q is 0.25mYou need to login to perform this action.
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