A) \[\frac{\sqrt{14}}{3}\]
B) \[\frac{\sqrt{85}}{5}\]
C) \[\sqrt{2}\]
D) \[\sqrt{3}\]
Correct Answer: B
Solution :
[b] From similar triangles APB and CBD, point P will be just visible if CD = 4 R \[\mu \sin i=1\times \sin r\] \[\mu \sin \left( \angle CDQ \right)=1\times \sin \left( \angle CDB \right)\] \[\mu \times \frac{R}{R\sqrt{17}}=1\times \frac{2R}{R\sqrt{20}}\Rightarrow \mu =\frac{2\sqrt{17}}{\sqrt{20}}=\frac{\sqrt{85}}{5}\]You need to login to perform this action.
You will be redirected in
3 sec