question_answer

A man whose eye level is 1.5 meters above the ground observe the angle of elevation of the tower to be\[60{}^\circ \]. If the distance of the man from the tower be 10 meters, the height of the tower is

A) \[(1.5+10\sqrt{3})m\]

B) \[10\sqrt{3}m\]

C) \[\left( 1.5+\frac{10}{\sqrt{3}} \right)m\]

D) None of these

Correct Answer: A

Solution :

[a] \[H=(10tan60{}^\circ +1.5)\] \[=(10\sqrt{3}+1.5)m\]