A) 0
B) 1
C) 2
D) 3
Correct Answer: B
Solution :
[b] If \[A+B+C=\pi ,\] then \[\cos mA+\cos mB+\cos mC\] \[=1-4\sin \frac{mA}{2}\sin \frac{mB}{2}\sin \frac{mC}{2}\] \[\therefore \] For \[m=2:\cos 2A+\cos 2B+\cos 2C\] \[=1-4\sin A\sin B\sin C\] \[\Rightarrow \cos 2A+\cos 2B+\cos 2C\] \[+4\sin A\sin B\operatorname{sinC}=1\]You need to login to perform this action.
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