A) \[\frac{11}{21}\]
B) \[\frac{8}{21}\]
C) \[\frac{10}{21}\]
D) \[\frac{7}{21}\]
Correct Answer: C
Solution :
[c] Total number of ways in which 4 persons can be selected out of \[3+2+4=9\] persons \[={{\,}^{9}}{{C}_{4}}\]\[=126.\] Number of ways in which a selection of 4 contains exactly 2 children\[{{=}^{4}}{{C}_{2}}{{\times }^{5}}{{C}_{2}}=60.\] \[\therefore \] Require probability \[=\frac{60}{126}=\frac{10}{21}\]
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