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JEE Main & Advanced Mathematics Probability Question Bank Self Evaluation Test - Probability-I

  • question_answer
    It has been found that if A and B play a game 12 times. A wins 6 times, B wins 4 times and they draw twice. A and B take part in a series of 3 games. The probability that they with alternately, is:

    A) \[5/12\]

    B) \[5/36\]

    C) \[19/27\]

    D) \[5/27\]

    Correct Answer: B

    Solution :

    [b] \[P(A)=\frac{6}{12}=\frac{1}{2},P(B)=\frac{4}{12}=\frac{1}{3}\] Req. probability \[=\frac{1}{2}.\frac{1}{3}.\frac{1}{2}+\frac{1}{3}.\frac{1}{2}.\frac{1}{3}=\frac{1}{12}+\frac{1}{18}=\frac{5}{36}\]


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