A) 0
B) 0.1
C) 0.5
D) 1
Correct Answer: C
Solution :
[c] As we know \[P(A\cup B)\le 1\] \[\therefore P(A)+P(B)-P(A\cap B)\le 1\] \[\Rightarrow 0.8+0.7-P(A\cap B)\le 1\] \[\Rightarrow P(A\cap B)\ge 1.5-1\] \[\Rightarrow P(A\cap B)\ge 0.5\] Hence, the minimum value of \[P(A\cap B)\] is 0.5.You need to login to perform this action.
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