A) \[\frac{1}{6}\]
B) \[\frac{1}{30}\]
C) \[\frac{11}{80}\]
D) \[\frac{23}{90}\]
Correct Answer: D
Solution :
[d] Nos. divisible by 6 are \[6,12,18...90.\] Nos. divisible by 8 are \[8,16,24...88.\] Now, total no. divisible by \[6=15\] And total no. divisible by \[8=11\] Now, the no. divisible by both 6 and 8 are 24, 48, 72. So, that no. divisibly by both 6 and \[8=3\] \[\therefore \] Probability (number divisible by 6 or 8) \[=\frac{15+11-3}{90}=\frac{23}{90}\]
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