A) \[\frac{2}{3}\]
B) \[\frac{4}{5}\]
C) \[\frac{7}{8}\]
D) \[\frac{11}{16}\]
Correct Answer: D
Solution :
[d] We hove; np =2=mean Npq=1=variance \[\Rightarrow p=\frac{1}{2};q=\frac{1}{2}\And n=4\] Required probability \[=P(x>1)\] \[=1-P(x\le 1)\] \[=1-[P(x=0)+P(x=1)]\] \[=1-{{[}^{4}}{{C}_{0}}{{q}^{4}}{{+}^{4}}{{C}_{1}}{{q}^{3}}{{p}^{1}}]\] \[=1-\frac{5}{16}=\frac{11}{16}\]
You need to login to perform this action.
You will be redirected in
3 sec
