JEE Main & Advanced Mathematics Probability Question Bank Self Evaluation Test - Probability-I

  • question_answer
    Three digits are chosen at random from 1, 2, 3, 4, 5, 6, 7, 8 and 9 without repeating any digit. What is the probability that the product is odd?

    A) \[\frac{2}{3}\]

    B) \[\frac{7}{48}\]

    C) \[\frac{5}{42}\]

    D) \[\frac{5}{108}\]

    Correct Answer: C

    Solution :

    [c] Total no. of 3-digit numbers \[=9\times 8\times 7=504\] For product to be odd, we have to choose only from odd numbers. \[\therefore \] Total no. of 3-digit no, whose product are odd \[=5\times 4\times 3=60\] \[\therefore \] Required probability \[=\frac{60}{504}=\frac{5}{42}\]


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