A) \[\frac{3}{8}\]
B) \[\frac{1}{6}\]
C) \[\frac{3}{5}\]
D) None of these
Correct Answer: B
Solution :
[b] The total number of ways in which 8 persons can speak is \[^{8}{{P}_{8}}=8!\] the number of ways in which, A, B and C can be arranged in the specified speaking order is \[^{8}{{C}_{3}}.\] There are 5! Ways in which the other five can speak. So, favourable number of ways is \[^{8}{{C}_{3}}\times 5!\] Hence, required probability \[=\frac{^{8}{{C}_{3}}\times 5!}{8!}=\frac{1}{6}.\]
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