JEE Main & Advanced Physics Mathematical Tools, Units & Dimensions Question Bank Self Evaluation Test - Physical World, Units and Measurements

  • question_answer
    If the dimensions of a physical quantity are given by \[{{M}^{a}}{{L}^{b}}{{T}^{c}}\], then the physical quantity will be

    A)  Velocity if \[a=1,\text{ }b=0,\text{ }c=-1\]

    B)  Acceleration if \[a=1,\text{ }b=1,\text{ }c=-2\]

    C)  Force if \[a=0,\text{ }b=-1,\text{ }c=-2\]

    D)  Pressure if \[a=1,\text{ }b=-1,\text{ }c=-2\]

    Correct Answer: D

    Solution :

    [d] Pressure \[=\frac{ML{{T}^{-2}}}{{{L}^{2}}}=[M{{L}^{-1}}{{T}^{-2}}]\] \[\Rightarrow a=1,b=-1,c=-2\]


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