A) \[[T],\,[{{T}^{-3}}]\]
B) \[[L],\,[L{{T}^{-4}}]\]
C) \[[{{T}^{-3}}],[T]\]
D) \[[L{{T}^{-4}}],[L]\]
Correct Answer: B
Solution :
[b] Dimensionally \[v=\frac{a}{t}\Rightarrow a=L{{T}^{-1}}\times T=L\] also dimensionally \[v=b{{t}^{3}}\Rightarrow b=\frac{L{{T}^{-1}}}{{{T}^{3}}}=L{{T}^{-4}}\]
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