A) \[[M{{L}^{2}}{{T}^{-2}}K]\]
B) \[[M{{L}^{2}}{{T}^{-2}}{{K}^{-1}}]\]
C) \[[M{{L}^{2}}{{T}^{2}}{{K}^{-1}}]\]
D) \[[{{L}^{2}}{{T}^{-2}}{{K}^{-1}}]\]
Correct Answer: D
Solution :
[d] \[s=\frac{Q}{m\theta }=\frac{M{{L}^{2}}{{T}^{-2}}}{MK}=[{{L}^{2}}{{T}^{-2}}{{K}^{-1}}]\]
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