A) 20
B) 4
C) 5
D) None of these
Correct Answer: B
Solution :
[b] \[^{20}{{C}_{1}}{{=}^{20}}{{C}_{19}}=20\] \[^{20}{{C}_{3}}={{\,}^{20}}{{C}_{17}}=20\times 19\times 3\] \[^{20}{{C}_{5}}{{=}^{20}}{{C}_{15}}=19\times 17\times 16\times 3\] \[^{20}{{C}_{7}}{{=}^{20}}{{C}_{13}}=19\times 17\times 16\times 15\] \[^{20}{{C}_{9}}{{=}^{20}}{{C}_{11}}=19\times 17\times 13\times 11\times 5\times 8\] Clearly G.C.D. = 4
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