JEE Main & Advanced Mathematics Permutations and Combinations Question Bank Self Evaluation Test - Permutations and Combinatioins

  • question_answer
    If 12 persons are seated in a row, the number of ways of selecting 3 persons from them, so that no two of them are seated next to each other is

    A) 85

    B) 100

    C) 120

    D) 240

    Correct Answer: C

    Solution :

    [c] The number of ways of selecting 3 persons from 12 people under the given condition: = Number of ways of arranging 3 people among 9 people seated in a row, so that no two of them are consecutive = Number of ways of choosing 3 places out of the 10 [8 in between and 2 extremes] \[{{=}^{10}}{{C}_{3}}=\frac{10\times 9\times 8}{3\times 2\times 1}=5\times 3\times 8=120\]


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