A) \[6:5\]
B) \[3:2\]
C) \[4:3\]
D) \[5:3\]
Correct Answer: D
Solution :
[d] \[p:\underset{5}{\mathop{TTH\,\,\,}}\,\underset{4}{\mathop{TH}}\,\underset{3}{\mathop{\,\,\,H\,\,}}\,\underset{2}{\mathop{T\,\,}}\,\underset{1}{\mathop{0}}\,\,\,\,\,\,\begin{matrix} place \\ ways \\ \end{matrix}\] Total no. of ways \[=5!=120\] Since all numbers are \[>20,000\] \[\therefore \] All numbers 2, 3,5,7,9 can come at first place. \[q:\underset{5}{\mathop{TTH}}\,\,\,\,\underset{4}{\mathop{\,TH}}\,\,\,\,\,\underset{3}{\mathop{H}}\,\underset{2}{\mathop{\,\,\,\,T\,\,\,\,\,}}\,\underset{1}{\mathop{0}}\,\,\,\,\,\,\,\,\,\begin{matrix} place \\ ways \\ \end{matrix}\] Total no. of ways \[=3\times 4!=72\] (\[\because \] 2 and 9 cannot be put at first place) So, \[p:q=120:72=5:3\]
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