JEE Main & Advanced Mathematics Permutations and Combinations Question Bank Self Evaluation Test - Permutations and Combinatioins

  • question_answer
    Four couples (husband and wife) decide to form a committee of four members. Find the number of different committees that can be formed in which no couple finds a place.

    A) 12

    B) 14

    C) 16

    D) 24

    Correct Answer: C

    Solution :

    [c] The number of committees of 4 gentlemen \[{{=}^{4}}{{C}_{4}}=1\] The number of committees of 3 gentlemen, 1 wife \[{{=}^{4}}{{C}_{3}}{{\times }^{1}}{{C}_{1}}\] (\[\because \] After selecting 3 gentlemen only 1 wife is left who can be included) The number of committees of 2 gentlemen, 2 wives \[{{=}^{4}}{{C}_{2}}{{\times }^{2}}{{C}_{2}}\] The number of committees of 1 gentleman, 3 wives \[{{=}^{4}}{{C}_{1}}{{\times }^{3}}{{C}_{3}}\] The number of committees of 4 wives = 1 \[\therefore \] The required number of committees \[=1+4+6+4+1=16\]


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