JEE Main & Advanced Mathematics Permutations and Combinations Question Bank Self Evaluation Test - Permutations and Combinatioins

  • question_answer
    There are 18 points in a plane such that no three of them are in the same line except five points which are collinear. The number of triangles formed by these points is:

    A) 816

    B) 806

    C) 805

    D) 813

    Correct Answer: B

    Solution :

    [b] A triangle can be formed by using three no collinear points. So, the number of triangles formed by 18 non-collinear points \[{{=}^{18}}{{C}_{3}}\] But according to the question, 5 points are collinear. Hence, exact number of triangles \[{{=}^{18}}{{C}_{3}}{{-}^{5}}{{C}_{3}}=\frac{18!}{3!15!}-\frac{5!}{3!2!}\] \[=\frac{16\times 17\times 18}{2\times 3}-\frac{4\times 5}{2}=816-10=806.\]


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