A) \[{{2}^{n-m-1}}-1\]
B) \[{{2}^{n-m-1}}\]
C) \[{{2}^{n-m}}\]
D) \[{{2}^{p-n+m-1}}\]
Correct Answer: B
Solution :
[b] Between m and n, there are \[\operatorname{n} - m -1\]elements. Each subset contains m and n and for all of other n - m -1 element, there are two possibilities so, no. of subset \[={{2}^{n-m-1}}.\]
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