JEE Main & Advanced Mathematics Permutations and Combinations Question Bank Self Evaluation Test - Permutations and Combinatioins

  • question_answer
    In a small village, there are 87 families, of which 52 families have at most 2 children. In a rural development programme 20 families are to be chosen for assistance, of which at least 18 families must have at most 2 children. In how many ways can the choice be made?

    A) \[^{52}{{C}_{18}}^{35}{{C}_{2}}\]

    B) \[^{52}{{C}_{18}}{{\times }^{35}}{{C}_{2}}{{+}^{52}}{{C}_{19}}{{\times }^{35}}{{C}_{1}}{{+}^{52}}{{C}_{20}}\]

    C) \[^{52}{{C}_{18}}{{+}^{35}}{{C}_{2}}{{+}^{52}}{{C}_{19}}\]

    D) \[^{52}{{C}_{18}}{{\times }^{35}}{{C}_{2}}{{+}^{35}}{{C}_{1}}{{\times }^{52}}{{C}_{19}}\]

    Correct Answer: B

    Solution :

    [b] The following are the number of possible choices: \[^{52}{{C}_{18}}{{\times }^{35}}{{C}_{2}}\] (18 families having at most 2 children and 2 selected from other type of families) \[^{52}{{C}_{19}}{{\times }^{35}}{{C}_{1}}\](19 families having at most 2 children and 1 selected from other type of families) \[^{52}{{C}_{20}}\] (All selected 20 families having at most 2 children). Hence, the total number of possible choices is: \[{{=}^{52}}{{C}_{18}}{{\times }^{35}}{{C}_{2}}{{+}^{52}}{{C}_{19}}{{\times }^{35}}{{C}_{1}}{{+}^{52}}{{C}_{20}}\]


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