A) \[\frac{(10)!}{6!}\]
B) \[\frac{(10)!}{24}\]
C) \[\frac{(9)!}{24}\]
D) None of these
Correct Answer: B
Solution :
[b] Selection of 6 guests = 10C6 Permutation of 6 on round table = 5! Permutation of 4 on round table = 3! Then, total number of arrangements \[{{=}^{10}}{{C}_{5}}.5!.3!\] \[=\frac{(10)!}{6!4!}.5!.3!=\frac{(10)!}{24}\]
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