JEE Main & Advanced Physics Wave Mechanics Question Bank Self Evaluation Test - Oscillations

  • question_answer
    The amplitude of a damped oscillator becomes\[{{\left( \frac{1}{3} \right)}^{rd}}\] in 2 seconds. If its amplitude after 6 seconds is\[\frac{1}{n}\] times the original amplitude, the value of n is              

    A) \[{{3}^{2}}\]

    B) \[{{3}^{3}}\]    

    C) \[\sqrt[3]{3}\]

    D) \[{{2}^{3}}\]

    Correct Answer: B

    Solution :

    [b] Amplitude of a damped oscillator at any instant t is given by \[A={{A}_{0}}{{e}^{-bt/2m}}\] where\[{{A}_{0}}\] is the original amplitude From question, When \[t=2s,\,A=\frac{{{A}_{0}}}{3}\,\,\therefore \,\frac{{{A}_{0}}}{3}={{A}_{0}}{{e}^{-2b/2m}}\]  or \[\frac{1}{3}={{e}^{-b/m}}\]             ?. (i) When \[t=6s,\,A=\frac{{{A}_{0}}}{n}\]      \[\therefore \,\frac{{{A}_{0}}}{n}={{A}_{0}}{{e}^{-6b/2m}}\] or,\[\frac{1}{n}={{e}^{-3b/m}}={{({{e}^{-b/m}})}^{3}}\]   or, \[\frac{1}{n}={{\left( \frac{1}{3} \right)}^{3}}\] \[\therefore \,n={{3}^{3}}\]          (Using eq. (i))


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