A) \[\pi \sqrt{\frac{2m}{k}}\]
B) \[\sqrt{\frac{2m\pi }{k}}\]
C) \[\sqrt{\frac{m\pi }{2k}}\]
D) \[\pi \sqrt{\frac{m}{2k}}\]
Correct Answer: A
Solution :
[a] \[2k\,{{\sin }^{2}}\theta ={{k}_{1}}\,or\,{{k}_{1}}=2k\,{{\sin }^{2}}\theta \] and \[{{k}_{2}}=2(2k){{\sin }^{2}}\beta \]You need to login to perform this action.
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