A) \[\pi /2\,s\]
B) \[\pi s\]
C) \[3\pi /2s\]
D) \[2\pi s\]
Correct Answer: B
Solution :
[b] Using \[{{v}^{2}}={{\omega }^{2}}({{a}^{2}}-{{y}^{2}})\] we have \[{{10}^{2}}={{\omega }^{2}}({{a}^{2}}-{{4}^{2}})\] and \[{{8}^{2}}={{\omega }^{2}}({{a}^{2}}-{{5}^{2}});\] so \[{{10}^{2}}-{{8}^{2}}={{\omega }^{2}}({{5}^{2}}-{{4}^{2}})=(3{{\omega }^{2}})\,or\,6=3\omega \] or \[\omega =2\,or\,T=2\pi /\omega =2\pi /2=\pi s.\]
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