JEE Main & Advanced Physics Wave Mechanics Question Bank Self Evaluation Test - Oscillations

  • question_answer
    The bob of a simple pendulum of mass m and total energy E will have maximum linear momentum equal to            

    A) \[\sqrt{\frac{2E}{m}}\]

    B) \[\sqrt{2mE}\]   

    C) \[2mE\]

    D) \[m{{E}^{2}}\]

    Correct Answer: B

    Solution :

    [b] \[{{p}_{\max }}=\sqrt{2m{{E}_{\max }}}\]


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