JEE Main & Advanced Physics Wave Mechanics Question Bank Self Evaluation Test - Oscillations

  • question_answer
    The displacement of a particle in SHM is\[x=10\sin \left( 2t-\frac{\pi }{6} \right)\] metre. When its displacement is 6 m, the velocity of the particle (in m s~1) is

    A) 8

    B) 24   

    C) 16

    D) 10

    Correct Answer: C

    Solution :

    [c] Given, \[x=10\sin \,\left( 2t-\frac{\pi }{6} \right)\] \[A=10\,and\,\omega =2Hz\] \[\therefore \,\,v=\omega \sqrt{{{A}^{2}}-{{d}^{2}}}=2\sqrt{{{(10)}^{2}}-{{(6)}^{2}}}\] \[2\sqrt{100-36}=2\times 8=16m\,{{s}^{-1}}\]


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