A) \[\frac{A-Z-8}{Z-4}\]
B) \[\frac{A-Z-4}{Z-8}\]
C) \[\frac{A-Z-12}{Z-4}\]
D) \[\frac{A-Z-4}{Z-2}\]
Correct Answer: B
Solution :
[b] As a result of emission of 1 \[\alpha \]-particle, the mass number decreases by 4 units and atomic number decreases by 2 units. And by the emission of 1 positron the atomic number decreases by 1 unit but mass number remains constant. \[\therefore \] Mass number of final nucleus \[=A-12\] Atomic number of final nucleus \[=Z-8\] \[\therefore \] Number of neutrons \[=(A-12)-(Z-8)\] \[=A-Z-4\] Number of protons \[=Z-8\] \[\therefore \] Required ratio \[=\frac{A-Z-4}{Z-8}\]
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