A) \[{{10}^{4}}\]
B) \[2\times {{10}^{5}}\]
C) \[7\times {{10}^{5}}\]
D) \[11\times {{10}^{5}}\]
Correct Answer: C
Solution :
[c] \[N={{N}_{0}}{{e}^{-\lambda /t}}={{10}^{6}}{{e}^{-\left[ \frac{In\,\,2}{20}\times 10 \right]}}\] \[={{10}^{6}}{{e}^{-In\,\,\sqrt{2}}}=\frac{{{10}^{6}}}{\sqrt{2}}=\,\,\approx \,\,7.07\times {{10}^{5}}\]
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