A) \[2.77\text{ }mg\]
B) \[2.77\text{ }g\]
C) \[2.77\times {{10}^{-23}}g\]
D) \[2.77\times {{10}^{-13}}kg\]
Correct Answer: D
Solution :
[d] \[\left| \frac{d/N}{dt} \right|=\lambda N\] Number of radius nuclei in \[mg=\frac{{{N}_{A}}m}{226}\] Decay constant, \[\lambda =\frac{0.693}{{{t}_{1/2}}}=\frac{0.693}{1620\times 3.16\times {{10}^{7}}}\] \[\left| \frac{dN}{dt} \right|=10=\frac{6.02\times {{10}^{23}}m}{226}\times \frac{0.693}{1620\times 3.16\times {{10}^{7}}}\] \[\therefore \,\,\,\,\,\,m=\frac{10\times 226\times 162\times 3.16\times {{10}^{7}}}{6.02\times {{10}^{23}}\times 0.693}\] \[=2.77\times {{10}^{-10}}g=2.77\times {{10}^{-13}}kg\]
You need to login to perform this action.
You will be redirected in
3 sec
