A) 15 minutes
B) 10 minutes
C) \[7\frac{1}{2}\]minutes
D) 5 minutes
Correct Answer: D
Solution :
[d] \[\frac{7}{8}\] of \[Cu\] decays in 15 minutes. \[\therefore \] \[Cu\] undecayed \[=N=1-\frac{7}{8}=\frac{1}{8}={{\left( \frac{1}{2} \right)}^{3}}\] \[\therefore \] No. of half lifes = 3 \[n=\frac{t}{T}\] or \[3=\frac{15}{T}\] \[\Rightarrow \] T = half-life period \[=\frac{15}{3}=5\] minutes
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