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JEE Main & Advanced Physics Nuclear Physics And Radioactivity Question Bank Self Evaluation Test - Nuclei

  • question_answer
    Two radioactive substances X and Y emit \[\alpha \] and \[\beta \] particles respectively. Their disintegration constants are in the ratio 2 : 3. To have equal probabilities of getting emission of \[\alpha \] and \[\beta \] particles, the ratio of number of atoms X to that of Fat any time instant is

    A)  2 : 3 

    B)  3 : 2

    C)    e : 1 

    D)  (e-1) : 1

    Correct Answer: B

    Solution :

    [b] \[{{N}_{1}}{{\lambda }_{1}}={{N}_{2}}{{\lambda }_{2}}\frac{{{\lambda }_{1}}}{{{\lambda }_{2}}}=\frac{2}{3}\Rightarrow \frac{{{N}_{2}}}{{{N}_{1}}}=\frac{2}{3}\] \[\Rightarrow \]  ratio of no. of nuclei of X to that of \[Y=3/2\]


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