JEE Main & Advanced Physics Nuclear Physics And Radioactivity Question Bank Self Evaluation Test - Nuclei

  • question_answer
    If nuclei of a radioactive element is produced at constant rate \[\alpha \] and they decays with decay constant\[\lambda \]. At t=0, number of nuclei is zero than the number of nuclei at time t is

    A)  \[\frac{\alpha }{\lambda }\left( 1-{{e}^{-\lambda t}} \right)\]

    B)  \[\alpha -\frac{\alpha }{\lambda }{{e}^{-\lambda t}}\]

    C)  \[\frac{\alpha }{\lambda }{{e}^{-\lambda t}}\]

    D)  \[\alpha \left( 1-{{e}^{-\lambda t}} \right)\]

    Correct Answer: A

    Solution :

    [a] \[\frac{dN}{dt}=\alpha -\lambda N\] \[\int_{0}^{N}{\frac{dN}{\alpha -\lambda N}}\,\,\,=\int_{0}^{t}{dt}\]     Solving \[N=\frac{\alpha }{\lambda }\,\,(1-{{e}^{-\lambda t}}).\]


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