A) \[t={{t}_{1}}+{{t}_{2}}\]
B) \[\frac{1}{t}=\frac{1}{{{t}_{1}}}+\frac{1}{{{t}_{2}}}\]
C) \[t=\frac{2{{t}_{1}}{{t}_{2}}}{{{t}_{1}}+{{t}_{2}}}\]
D) \[t=\frac{{{t}_{1}}+{{t}_{2}}}{2}\]
Correct Answer: B
Solution :
[b] \[\frac{dN}{dt}=-N\,({{\lambda }_{1}}+{{\lambda }_{2}})=-N\lambda \] \[\Rightarrow \,\,\,\,\,\,\,\lambda ={{\lambda }_{1}}+{{\lambda }_{2}}\] so \[\frac{1}{t}=\frac{1}{{{t}_{1}}}+\frac{1}{{{t}_{2}}}\,\,\,\,\,\left[ as\,\,\,\lambda =\frac{0.693}{t} \right]\]
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