A) 3.8 days
B) 16.5 days
C) 33 days
D) 76 days.
Correct Answer: B
Solution :
[b] \[{{t}_{1/2}}=3.8\] day \[\therefore \,\,\,\,\,\,\,\,\,\,\,\,\lambda =\frac{0.693}{{{t}_{1/2}}}=\frac{0.693}{3.8}=0.182\] If the initial number of atom is \[a={{A}_{0}}\] then after time t the number of atoms is \[a/20=A\]. We have to find t. \[t=\frac{2.303}{\lambda }\log \frac{{{A}_{0}}}{A}=\frac{2.303}{0.182}\log \frac{a}{a/20}\] \[=\frac{2.303}{0.182}\log 20=16.46\] days
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