A) \[6.2\times {{10}^{21}}\]
B) \[7.5\times {{10}^{21}}\]
C) \[1.25\times {{10}^{22}}\]
D) \[1.75\times {{10}^{22}}\]
Correct Answer: B
Solution :
[b] We know that \[{{N}_{\beta }}={{N}_{0}}(1-{{e}^{-\lambda t}})\] \[{{N}_{\beta }}=\frac{6.023\times {{10}^{23}}}{24}\left[ 1-e\frac{\ell \,n\,2}{15}\times 7.5 \right]\] on solving we get, \[{{N}_{\beta }}=7.4\times {{10}^{21}}\] If \[\alpha \] and B are emitted simultaneously.
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