A) 1 : 2
B) 4 : 1
C) 1 : 4
D) 2 :1
Correct Answer: C
Solution :
[c] Ratio of number of half-life taken is given as: After 16 days \[{{T}_{AI/2}}=\frac{16}{4}=4;\] \[{{T}_{BI/2}}=\frac{16}{8}=2\] \[N={{N}_{0}}{{\left( \frac{1}{2} \right)}^{n}}\Rightarrow \frac{{{N}_{A}}}{{{N}_{B}}}=\frac{1}{{{2}^{4}}}:\frac{1}{{{2}^{2}}}={{2}^{2}}:{{2}^{4}}\] \[=4:16,\,\,=1:4\]
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