JEE Main & Advanced Physics Nuclear Physics And Radioactivity Question Bank Self Evaluation Test - Nuclei

  • question_answer
    If 200 MeV energy is released in the fission of a single \[{{U}^{235}}\] nucleus, the number of fissions required per second to produce 1 kilowatt power shall be(Given \[\,1eV=\text{ }1.6\times {{10}^{-19}}J\])

    A)  \[3.125\times {{10}^{13}}\]

    B)  \[\,3.125\times {{10}^{14}}\]

    C)  \[3.125\times {{10}^{15}}\]

    D)  \[3.125\times {{10}^{16}}\]

    Correct Answer: A

    Solution :

    [a]  \[P-n\left( \frac{E}{t} \right)\Rightarrow 1000=\frac{n\times 200\times {{10}^{6}}\times 1.6\times {{10}^{-19}}}{t}\] \[\Rightarrow \,\,\,\,\,\,\,\,\,\frac{n}{t}=3.125\times {{10}^{13}}.\]


You need to login to perform this action.
You will be redirected in 3 sec spinner