A) \[3\times {{10}^{-15}}m\]
B) \[1.5\times {{10}^{-15}}m\]
C) \[6\times {{10}^{-15}}m\]
D) \[4.5\times {{10}^{-15}}m\]
Correct Answer: C
Solution :
[c] Radius R os a nucleus changes with the nucleon number A of the nucleus as \[R=1.3\times {{10}^{-15}}\times {{A}^{1/3}}m\] Hence, \[\frac{{{R}_{2}}}{{{R}_{1}}}={{\left( \frac{{{A}_{2}}}{{{A}_{1}}} \right)}^{1/3}}={{\left( \frac{128}{16} \right)}^{1/3}}={{(8)}^{1/3}}=2\] \[\therefore \,\,\,\,\,\,\,\,\,\,{{R}_{2}}=2{{R}_{1}}=2(3\times {{10}^{-15}})m=6\times {{10}^{-15}}m\]
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