A) \[0.96\text{ }gm\]
B) \[0.8\text{ }gm\,\]
C) \[4\times {{10}^{-2}}gm~~~~~\]
D) \[6.6\times {{10}^{-5}}gm\]
Correct Answer: C
Solution :
[c] Power level of reactor, \[P=\frac{E}{\Delta t}=\frac{\Delta m{{c}^{2}}}{\Delta t}\] mass of the fuel consumed per hour in the reactor, \[\frac{\Delta m}{\Delta t}=\frac{P}{{{c}^{2}}}=\frac{{{10}^{9}}}{{{(3\times {{10}^{8}})}^{2}}}kg/\sec =\frac{3600\times {{10}^{9}}}{9\times {{10}^{16}}}\] \[\times {{10}^{3}}\frac{gm}{hr}\]
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