2. Questions Bank
  3. JEE Main & Advanced
  4. Physics
  5. Nuclear Physics And Radioactivity

JEE Main & Advanced Physics Nuclear Physics And Radioactivity Question Bank Self Evaluation Test - Nuclei

  • question_answer
    Two deuterons undergo nuclear fusion to form a Helium nucleus. Energy released in this process is : (given binding energy per nucleon for deuteron=1. 1 MeV and for helium=7.0 MeV)

    A)  30.2 MeV

    B)  32.4 MeV

    C)  23.6 MeV

    D)  25.8 MeV

    Correct Answer: C

    Solution :

    [c] \[_{1}{{H}^{2}}{{+}_{1}}{{H}^{2}}{{\to }_{2}}H{{e}^{4}}\] Total binding energy of two deuterium nuclei \[=1.1\times 4=4.4\,MeV\] Binding energy of a \[{{(}_{2}}H{{e}^{4}})\] nuclei \[=4\times 7=28\text{ }MeV\] Energy released in this process \[=28-4.4=23.6MeV\]


You need to login to perform this action.
You will be redirected in 3 sec spinner