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JEE Main & Advanced Physics Nuclear Physics And Radioactivity Question Bank Self Evaluation Test - Nuclei

  • question_answer
    The mass of \[_{7}{{N}^{15}}\] is 15.00011 amu, mass of \[_{8}{{O}^{16}}\] is 15.99492 amu and \[mp=1.00783\text{ }amu\] Determine binding energy of last proton of\[_{8}{{O}^{16}}\].

    A)  2.13 MeV

    B)  0.13 MeV

    C)  10 MeV

    D)  12.13 MeV

    Correct Answer: D

    Solution :

    [d] \[M{{(}_{8}}{{O}^{16}})=M{{(}_{7}}{{N}^{15}})+1{{m}_{P}}\] binding energy of last proton \[=M({{N}^{15}})+{{m}_{P}}-M{{(}_{1}}{{O}^{16}})\] \[=15.00011+1.00783-15.99492\] \[=0.01302\text{ }amu=12.13\text{ }MeV\]


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